What is the general solution for -8cos(x)-7=0 ?

The general solution for -8cos(x)-7=0 is x=2.63623…+2pin,x=-2.63623…+2pin

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-8cos(x)-7=0

- 8 cos (x) - 7 = 0

x = 2.63623 \dots + 2 πn, x = - 2.63623 \dots + 2 πn

Solution steps

- 8 cos (x) - 7 = 0

Move

7

to the right side

- 8 cos (x) = 7

Divide both sides by

- 8

cos (x) = - \frac{7}{8}

Apply trig inverse properties

x = arccos (- \frac{7}{8}) + 2 πn, x = - arccos (- \frac{7}{8}) + 2 πn

Show solutions in decimal form

x = 2.63623 \dots + 2 πn, x = - 2.63623 \dots + 2 πn

3 sin (2 x) - 3 cos (x) = 0

- 20 cos^{2} (x) - 36 cos (x) = 16

cos (3 x) = \frac{1}{2}, 0 \leq x < 2 π

- sin (x) - 2 cos (x) = 1

tan (2 x) + 1 = sec (2 x), 0 \leq x \leq 2 π

What is the general solution for -8cos(x)-7=0 ?
The general solution for -8cos(x)-7=0 is x=2.63623…+2pin,x=-2.63623…+2pin