What is the general solution for cos^2(θ)=1+sin(θ) ?

The general solution for cos^2(θ)=1+sin(θ) is θ=(3pi)/2+2pin,θ=2pin,θ=pi+2pin

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cos^2(θ)=1+sin(θ)

cos^{2} (θ) = 1 + sin (θ)

θ = \frac{3 π}{2} + 2 πn, θ = 2 πn, θ = π + 2 πn

Solution steps

cos^{2} (θ) = 1 + sin (θ)

Subtract

1 + sin (θ)

from both sides

cos^{2} (θ) - 1 - sin (θ) = 0

Rewrite using trig identities

- sin (θ) - sin^{2} (θ) = 0

Solve by substitution

sin (θ) = - 1, sin (θ) = 0

sin (θ) = - 1 : θ = \frac{3 π}{2} + 2 πn

sin (θ) = 0 : θ = 2 πn, θ = π + 2 πn

Combine all the solutions

θ = \frac{3 π}{2} + 2 πn, θ = 2 πn, θ = π + 2 πn

\frac{2}{5} cos (x) = \frac{2}{5}

sin^{2} (x) = 6 (cos (- x) + 1)

2 sin (θ) = 3 cos (θ)

3 sin^{2} (x) = sin (x) + 2

sin (θ) = - \frac{7}{25}, cos (\frac{θ}{2}), 27 0^{\circ} < θ < 36 0^{\circ}

What is the general solution for cos^2(θ)=1+sin(θ) ?
The general solution for cos^2(θ)=1+sin(θ) is θ=(3pi)/2+2pin,θ=2pin,θ=pi+2pin