What is the general solution for sin(x+pi/4)-sin(x-pi/4)=0 ?

The general solution for sin(x+pi/4)-sin(x-pi/4)=0 is x= pi/2+2pin,x=(3pi)/2+2pin

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sin(x+pi/4)-sin(x-pi/4)=0

sin (x + \frac{π}{4}) - sin (x - \frac{π}{4}) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

sin (x + \frac{π}{4}) - sin (x - \frac{π}{4}) = 0

Rewrite using trig identities

2 cos (x) = 0

Divide both sides by

2

cos (x) = 0

General solutions for

cos (x) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

4 tan (x) - tan^{2} (x) = 1

x, arcsin (y) = arcsin (x) + \frac{( π )}{4}

18 sin^{2} (x) - 9 sin (x) = 0

3 sin^{2} (θ) + 6 sin (θ) - 11 = 7 sin (θ) - 9

x, 2 cos (x) - 3 = 0

What is the general solution for sin(x+pi/4)-sin(x-pi/4)=0 ?
The general solution for sin(x+pi/4)-sin(x-pi/4)=0 is x= pi/2+2pin,x=(3pi)/2+2pin