What is the general solution for sin(x)+cos(x)=0,0<= x<= 2pi ?

The general solution for sin(x)+cos(x)=0,0<= x<= 2pi is x=(3pi)/4 ,x=(7pi)/4

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sin(x)+cos(x)=0,0<= x<= 2pi

sin (x) + cos (x) = 0, 0 \leq x \leq 2 π

x = \frac{3 π}{4}, x = \frac{7 π}{4}

Solution steps

sin (x) + cos (x) = 0, 0 \leq x \leq 2 π

Rewrite using trig identities

tan (x) + 1 = 0

Move

1

to the right side

tan (x) = - 1

General solutions for

tan (x) = - 1

x = \frac{3 π}{4} + πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{3 π}{4}, x = \frac{7 π}{4}

tan^{2} (θ) + 6 tan (θ) + 7 = 0

cos (\frac{π x}{2}) = 0

arccot (x) = \frac{π}{2}

cos (2 θ) + cos (4 θ) = 0

6 sin (A) - 3 = 0

What is the general solution for sin(x)+cos(x)=0,0<= x<= 2pi ?
The general solution for sin(x)+cos(x)=0,0<= x<= 2pi is x=(3pi)/4 ,x=(7pi)/4