What is the general solution for sin(A)cos(A)=sin(A) ?

The general solution for sin(A)cos(A)=sin(A) is A=2pin,A=pi+2pin

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sin(A)cos(A)=sin(A)

sin (A) cos (A) = sin (A)

A = 2 πn, A = π + 2 πn

Solution steps

sin (A) cos (A) = sin (A)

Subtract

sin (A)

from both sides

sin (A) cos (A) - sin (A) = 0

Factor

sin (A) cos (A) - sin (A) : sin (A) (cos (A) - 1)

sin (A) (cos (A) - 1) = 0

Solving each part separately

sin (A) = 0 or cos (A) - 1 = 0

sin (A) = 0 : A = 2 πn, A = π + 2 πn

cos (A) - 1 = 0 : A = 2 πn

Combine all the solutions

A = 2 πn, A = π + 2 πn

tan (\frac{x}{2} - \frac{π}{4}) = 1

3 sin (θ) = 1

sin (A) tan (A) = sin (A)

12 sin^{2} (x) + cos (x) - 5 = 1

3 tan (θ) + 10 = 0

What is the general solution for sin(A)cos(A)=sin(A) ?
The general solution for sin(A)cos(A)=sin(A) is A=2pin,A=pi+2pin