What is the general solution for 2= 1/2 [1+arctan(1/(1+C))] ?

The general solution for 2= 1/2 [1+arctan(1/(1+C))] is No Solution for C\in\mathbb{R}

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2= 1/2 [1+arctan(1/(1+C))]

2 = \frac{1}{2} [1 + arctan (\frac{1}{1 + C})]

No Solution for C \in R

Solution steps

2 = \frac{1}{2} [1 + arctan (\frac{1}{1 + C})]

Switch sides

\frac{1}{2} [1 + arctan (\frac{1}{1 + C})] = 2

Multiply both sides by

2

1 + arctan (\frac{1}{1 + C}) = 4

Move

1

to the right side

arctan (\frac{1}{1 + C}) = 3

- \frac{π}{2} < arctan (x) < \frac{π}{2}

No Solution for C \in R

x, tan (x) = \frac{1}{2}

t, x = sin^{2} (t)

2 sin^{2} (θ) - 3 sin (θ) - 2 = 0, 0 \leq θ < 2 π

sin (θ) + cos (θ) = - 2

cot (2 x) = 1.732, 0 \leq x \leq 2 π

What is the general solution for 2= 1/2 [1+arctan(1/(1+C))] ?
The general solution for 2= 1/2 [1+arctan(1/(1+C))] is No Solution for C\in\mathbb{R}