What is the general solution for tan^2(x)-3.31tan(x)+1.55=0 ?

The general solution for tan^2(x)-3.31tan(x)+1.55=0 is x=1.22149…+pin,x=0.51396…+pin

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tan^2(x)-3.31tan(x)+1.55=0

tan^{2} (x) - 3.31 tan (x) + 1.55 = 0

x = 1.22149 \dots + πn, x = 0.51396 \dots + πn

Solution steps

tan^{2} (x) - 3.31 tan (x) + 1.55 = 0

Solve by substitution

tan (x) = \frac{331 + 47561}{200}, tan (x) = \frac{331 - 47561}{200}

tan (x) = \frac{331 + 47561}{200} : x = arctan (\frac{331 + 47561}{200}) + πn

tan (x) = \frac{331 - 47561}{200} : x = arctan (\frac{331 - 47561}{200}) + πn

Combine all the solutions

x = arctan (\frac{331 + 47561}{200}) + πn, x = arctan (\frac{331 - 47561}{200}) + πn

Show solutions in decimal form

x = 1.22149 \dots + πn, x = 0.51396 \dots + πn

sec^{2} (x) - 9 = 0

cos^{2} (x) + 2 sin (x) - 1 = 0

6 - cos^{2} (θ) = 5

2 sec (x) + 2 = 6

14928 = \frac{18177}{( 1 + 0.387 cos ( x ) )}

What is the general solution for tan^2(x)-3.31tan(x)+1.55=0 ?
The general solution for tan^2(x)-3.31tan(x)+1.55=0 is x=1.22149…+pin,x=0.51396…+pin