What is the general solution for cos^2(x)+2sin(x)-1=0 ?

The general solution for cos^2(x)+2sin(x)-1=0 is x=2pin,x=pi+2pin

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cos^2(x)+2sin(x)-1=0

cos^{2} (x) + 2 sin (x) - 1 = 0

x = 2 πn, x = π + 2 πn

Solution steps

cos^{2} (x) + 2 sin (x) - 1 = 0

Rewrite using trig identities

- sin^{2} (x) + 2 sin (x) = 0

Solve by substitution

sin (x) = 0, sin (x) = 2

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 2 :

No Solution

Combine all the solutions

x = 2 πn, x = π + 2 πn

6 - cos^{2} (θ) = 5

2 sec (x) + 2 = 6

14928 = \frac{18177}{( 1 + 0.387 cos ( x ) )}

sin^{2} (θ) - 3 cos (θ) = 4

sec^{2} (x) - 2 = 0, 0 \leq x \leq 2 π

What is the general solution for cos^2(x)+2sin(x)-1=0 ?
The general solution for cos^2(x)+2sin(x)-1=0 is x=2pin,x=pi+2pin