What is the general solution for tan^2(x)+4tan(x)-5=0 ?

The general solution for tan^2(x)+4tan(x)-5=0 is x= pi/4+pin,x=-1.37340…+pin

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tan^2(x)+4tan(x)-5=0

tan^{2} (x) + 4 tan (x) - 5 = 0

x = \frac{π}{4} + πn, x = - 1.37340 \dots + πn

Solution steps

tan^{2} (x) + 4 tan (x) - 5 = 0

Solve by substitution

tan (x) = 1, tan (x) = - 5

tan (x) = 1 : x = \frac{π}{4} + πn

tan (x) = - 5 : x = arctan (- 5) + πn

Combine all the solutions

x = \frac{π}{4} + πn, x = arctan (- 5) + πn

Show solutions in decimal form

x = \frac{π}{4} + πn, x = - 1.37340 \dots + πn

3 sin^{2} (x) - 6 sin (x) = 0

2 cos^{2} (θ) = 3 sin (θ)

sin^{2} (θ) = 8 sin (θ) + 9

x, e^{c o s (y)} = cos (x)

10 sin (3 x) = 5

What is the general solution for tan^2(x)+4tan(x)-5=0 ?
The general solution for tan^2(x)+4tan(x)-5=0 is x= pi/4+pin,x=-1.37340…+pin