What is the general solution for cos^2(x)tan^2(x)csc^2(x)=sin(x) ?

The general solution for cos^2(x)tan^2(x)csc^2(x)=sin(x) is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos^2(x)tan^2(x)csc^2(x)=sin(x)

cos^{2} (x) tan^{2} (x) csc^{2} (x) = sin (x)

No Solution for x \in R

Solution steps

cos^{2} (x) tan^{2} (x) csc^{2} (x) = sin (x)

Subtract

sin (x)

from both sides

cos^{2} (x) tan^{2} (x) csc^{2} (x) - sin (x) = 0

Express with sin, cos

1 - sin (x) = 0

Move

1

to the right side

- sin (x) = - 1

Divide both sides by

- 1

sin (x) = 1

General solutions for

sin (x) = 1

x = \frac{π}{2} + 2 πn

Since the equation is undefined for:

\frac{π}{2} + 2 πn

No Solution for x \in R

cos (a) - sin (a) = cot (a) cos (a)

15 cos (\frac{2 π}{365} t) + 43 = 30

tan^{2} (x) = 2 sec (x) - 1

cos (z) = 1

cos (z) = 5

What is the general solution for cos^2(x)tan^2(x)csc^2(x)=sin(x) ?
The general solution for cos^2(x)tan^2(x)csc^2(x)=sin(x) is No Solution for x\in\mathbb{R}