What is the general solution for 1+sqrt(3)tan(θ)=2 ?

The general solution for 1+sqrt(3)tan(θ)=2 is θ= pi/6+pin

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1+sqrt(3)tan(θ)=2

1 + 3 tan (θ) = 2

θ = \frac{π}{6} + πn

Solution steps

1 + 3 tan (θ) = 2

Move

1

to the right side

3 tan (θ) = 1

Divide both sides by

3

tan (θ) = \frac{3}{3}

General solutions for

tan (θ) = \frac{3}{3}

θ = \frac{π}{6} + πn

sec (3 θ) = - 1

x, 2 sin (x) = 0

y, arctan (x + y) = x

sin (x) = 2.4

6 cos (θ) - 5 = 0

What is the general solution for 1+sqrt(3)tan(θ)=2 ?
The general solution for 1+sqrt(3)tan(θ)=2 is θ= pi/6+pin