What is the general solution for sin(t)=-1/(sqrt(2)) ?

The general solution for sin(t)=-1/(sqrt(2)) is t=(5pi)/4+2pin,t=(7pi)/4+2pin

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sin(t)=-1/(sqrt(2))

sin (t) = - \frac{1}{2}

t = \frac{5 π}{4} + 2 πn, t = \frac{7 π}{4} + 2 πn

Solution steps

sin (t) = - \frac{1}{2}

Simplify

- \frac{1}{2} : - \frac{2}{2}

General solutions for

sin (t) = - \frac{2}{2}

t = \frac{5 π}{4} + 2 πn, t = \frac{7 π}{4} + 2 πn

5 sin^{2} (x) = - 11 sin (x) - 6

6 sin (x) - 2 cos (x) = 7

csc^{2} (x) + 4 csc (x) - 5 = 0

90 + 45 cos (\frac{t ^{2}}{18}) - 100 = 0

3 tan^{3} (x) + 3 tan^{2} (x) - tan (x) - 1 = 0

What is the general solution for sin(t)=-1/(sqrt(2)) ?
The general solution for sin(t)=-1/(sqrt(2)) is t=(5pi)/4+2pin,t=(7pi)/4+2pin