What is the general solution for cos(x)-1=0,0<= x<= 2pi ?

The general solution for cos(x)-1=0,0<= x<= 2pi is x=0,x=2pi

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cos(x)-1=0,0<= x<= 2pi

cos (x) - 1 = 0, 0 \leq x \leq 2 π

x = 0, x = 2 π

Solution steps

cos (x) - 1 = 0, 0 \leq x \leq 2 π

Move

1

to the right side

cos (x) = 1

General solutions for

cos (x) = 1

x = 0 + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = 0, x = 2 π

sin (x) = \frac{4.8}{5.5}

2 cos^{2} (x) = 4 - 5 sin (x)

2 csc (2 x) + 2 = 0

x, cos (x) = - sin (x)

csc (x) - 2 sin (x) = 0

What is the general solution for cos(x)-1=0,0<= x<= 2pi ?
The general solution for cos(x)-1=0,0<= x<= 2pi is x=0,x=2pi