What is the general solution for (2sin(θ)-sqrt(3))(sin(θ)-1)=0 ?

The general solution for (2sin(θ)-sqrt(3))(sin(θ)-1)=0 is θ= pi/3+2pin,θ=(2pi)/3+2pin,θ= pi/2+2pin

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(2sin(θ)-sqrt(3))(sin(θ)-1)=0

(2 sin (θ) - 3) (sin (θ) - 1) = 0

θ = \frac{π}{3} + 2 πn, θ = \frac{2 π}{3} + 2 πn, θ = \frac{π}{2} + 2 πn

Solution steps

(2 sin (θ) - 3) (sin (θ) - 1) = 0

Solving each part separately

2 sin (θ) - 3 = 0 or sin (θ) - 1 = 0

2 sin (θ) - 3 = 0 : θ = \frac{π}{3} + 2 πn, θ = \frac{2 π}{3} + 2 πn

sin (θ) - 1 = 0 : θ = \frac{π}{2} + 2 πn

Combine all the solutions

θ = \frac{π}{3} + 2 πn, θ = \frac{2 π}{3} + 2 πn, θ = \frac{π}{2} + 2 πn

20 sin^{2} (x) + cos (x) - 19 = 0

sin^{2} (y) = 1

2 cos (2 θ) + 15 cos (θ) + 5 = 7 cos (θ)

tan^{2} (x) = 2 - tan (x)

- 3 = - 2 + tan (θ)

What is the general solution for (2sin(θ)-sqrt(3))(sin(θ)-1)=0 ?
The general solution for (2sin(θ)-sqrt(3))(sin(θ)-1)=0 is θ= pi/3+2pin,θ=(2pi)/3+2pin,θ= pi/2+2pin