What is the general solution for cos(2x-(3pi)/4)+1/(sqrt(2))=0 ?

The general solution for cos(2x-(3pi)/4)+1/(sqrt(2))=0 is x=(3pi)/4+pin,x=pin+pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(2x-(3pi)/4)+1/(sqrt(2))=0

cos (2 x - \frac{3 π}{4}) + \frac{1}{2} = 0

x = \frac{3 π}{4} + πn, x = πn + π

Solution steps

cos (2 x - \frac{3 π}{4}) + \frac{1}{2} = 0

Move

\frac{1}{2}

to the right side

cos (2 x - \frac{3 π}{4}) = - \frac{2}{2}

General solutions for

cos (2 x - \frac{3 π}{4}) = - \frac{2}{2}

2 x - \frac{3 π}{4} = \frac{3 π}{4} + 2 πn, 2 x - \frac{3 π}{4} = \frac{5 π}{4} + 2 πn

Solve

2 x - \frac{3 π}{4} = \frac{3 π}{4} + 2 πn : x = \frac{3 π}{4} + πn

Solve

2 x - \frac{3 π}{4} = \frac{5 π}{4} + 2 πn : x = πn + π

x = \frac{3 π}{4} + πn, x = πn + π

2 sin (x - \frac{π}{3}) + 2 = 0

sin^{2} (θ) + 3 = 2 cos^{2} (θ) + 4 sin (θ)

2 cos (2 x) + 3 = 4 cos (x)

sin (θ) = \frac{1}{4}, cos (θ)

2 sin^{2} (β) = 9 sin (β) - 4

What is the general solution for cos(2x-(3pi)/4)+1/(sqrt(2))=0 ?
The general solution for cos(2x-(3pi)/4)+1/(sqrt(2))=0 is x=(3pi)/4+pin,x=pin+pi