What is the general solution for cos(3θ)=1,0<= θ<= 2pi ?

The general solution for cos(3θ)=1,0<= θ<= 2pi is θ=0,θ=(2pi)/3 ,θ=(4pi)/3 ,θ=2pi

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cos(3θ)=1,0<= θ<= 2pi

cos (3 θ) = 1, 0 \leq θ \leq 2 π

θ = 0, θ = \frac{2 π}{3}, θ = \frac{4 π}{3}, θ = 2 π

Solution steps

cos (3 θ) = 1, 0 \leq θ \leq 2 π

General solutions for

cos (3 θ) = 1

3 θ = 0 + 2 πn

Solve

3 θ = 0 + 2 πn : θ = \frac{2 πn}{3}

θ = \frac{2 πn}{3}

Solutions for the range

0 \leq θ \leq 2 π

θ = 0, θ = \frac{2 π}{3}, θ = \frac{4 π}{3}, θ = 2 π

3 \cdot sin (\frac{x}{2}) + cos (x) = 1

sin (2 x) = \frac{2}{3}

tan^{3} (θ) + tan^{2} (θ) - 3 tan (θ) - 3 = 0

x, sec (x) tan (x) = 0

csc (x) = \frac{1}{4}

What is the general solution for cos(3θ)=1,0<= θ<= 2pi ?
The general solution for cos(3θ)=1,0<= θ<= 2pi is θ=0,θ=(2pi)/3 ,θ=(4pi)/3 ,θ=2pi