What is the general solution for tan(θ)+sqrt(3)=0,0<= θ<= 2pi ?

The general solution for tan(θ)+sqrt(3)=0,0<= θ<= 2pi is θ=(2pi)/3 ,θ=(5pi)/3

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tan(θ)+sqrt(3)=0,0<= θ<= 2pi

tan (θ) + 3 = 0, 0 \leq θ \leq 2 π

θ = \frac{2 π}{3}, θ = \frac{5 π}{3}

Solution steps

tan (θ) + 3 = 0, 0 \leq θ \leq 2 π

Move

3

to the right side

tan (θ) = - 3

General solutions for

tan (θ) = - 3

θ = \frac{2 π}{3} + πn

Solutions for the range

0 \leq θ \leq 2 π

θ = \frac{2 π}{3}, θ = \frac{5 π}{3}

2 tan (3 x) = 2

4 cot (x) = 11, 0^{\circ} \leq x < 36 0^{\circ}

sin (θ) + 0.755 = 0

- 4 cos^{2} (x) + 42 sin (x) + 6 = 0

sin (2 x - 1 0^{\circ}) = 0.4

What is the general solution for tan(θ)+sqrt(3)=0,0<= θ<= 2pi ?
The general solution for tan(θ)+sqrt(3)=0,0<= θ<= 2pi is θ=(2pi)/3 ,θ=(5pi)/3