What is the general solution for cos(θ)-0.018=0 ?

The general solution for cos(θ)-0.018=0 is θ=1.55279…+2pin,θ=2pi-1.55279…+2pin

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cos(θ)-0.018=0

cos (θ) - 0.018 = 0

θ = 1.55279 \dots + 2 πn, θ = 2 π - 1.55279 \dots + 2 πn

Solution steps

cos (θ) - 0.018 = 0

Move

0.018

to the right side

cos (θ) = 0.018

Apply trig inverse properties

θ = arccos (0.018) + 2 πn, θ = 2 π - arccos (0.018) + 2 πn

Show solutions in decimal form

θ = 1.55279 \dots + 2 πn, θ = 2 π - 1.55279 \dots + 2 πn

3 sin (θ) + 3 = 3

6 cos^{2} (x) + 12 cos (x) + 6 = 0

9 cos^{2} (x) + sin^{2} (x) = 3

(sin (x) + cos (x)) = 0

tan^{2} (θ) = 1 - sec^{2} (θ)

What is the general solution for cos(θ)-0.018=0 ?
The general solution for cos(θ)-0.018=0 is θ=1.55279…+2pin,θ=2pi-1.55279…+2pin