What is the general solution for sin(d)=0.19 ?

The general solution for sin(d)=0.19 is d=0.19116…+2pin,d=pi-0.19116…+2pin

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sin(d)=0.19

sin (d) = 0.19

d = 0.19116 \dots + 2 πn, d = π - 0.19116 \dots + 2 πn

Solution steps

sin (d) = 0.19

Apply trig inverse properties

d = arcsin (0.19) + 2 πn, d = π - arcsin (0.19) + 2 πn

Show solutions in decimal form

d = 0.19116 \dots + 2 πn, d = π - 0.19116 \dots + 2 πn

2 sin^{2} (4 x) = 1

(sin (x) + cos (x))^{2} = 1 + sin^{2} (x)

x, y = sin (x) y

1 \cdot sin (x) = 1.5 \cdot sin (\frac{x}{2})

sin (3 θ) = - 1, 0 \leq x \leq 2 π

What is the general solution for sin(d)=0.19 ?
The general solution for sin(d)=0.19 is d=0.19116…+2pin,d=pi-0.19116…+2pin