What is the general solution for 2sin^2(x)=-5sin(x)-3 ?

The general solution for 2sin^2(x)=-5sin(x)-3 is x=(3pi)/2+2pin

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2sin^2(x)=-5sin(x)-3

2 sin^{2} (x) = - 5 sin (x) - 3

x = \frac{3 π}{2} + 2 πn

Solution steps

2 sin^{2} (x) = - 5 sin (x) - 3

Solve by substitution

sin (x) = - 1, sin (x) = - \frac{3}{2}

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

sin (x) = - \frac{3}{2} :

No Solution

Combine all the solutions

x = \frac{3 π}{2} + 2 πn

sin (7 x) = 0, 0 \leq x \leq 2 π

13 cos (C) - 1 = 4 cos (C) - 8

sin (x) = - 0.2672

sin (x) = \frac{3}{10}

sin (2 x) = - \frac{2}{2}, 0 \leq x < 2 π

What is the general solution for 2sin^2(x)=-5sin(x)-3 ?
The general solution for 2sin^2(x)=-5sin(x)-3 is x=(3pi)/2+2pin