What is the general solution for cos(3θ)=-(sqrt(3))/2 ?

The general solution for cos(3θ)=-(sqrt(3))/2 is θ=(5pi}{18}+(2pin)/3 ,θ=(7pi)/(18)+\frac{2pin)/3

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cos(3θ)=-(sqrt(3))/2

cos (3 θ) = - \frac{3}{2}

θ = \frac{5 π}{18} + \frac{2 πn}{3}, θ = \frac{7 π}{18} + \frac{2 πn}{3}

Solution steps

cos (3 θ) = - \frac{3}{2}

General solutions for

cos (3 θ) = - \frac{3}{2}

3 θ = \frac{5 π}{6} + 2 πn, 3 θ = \frac{7 π}{6} + 2 πn

Solve

3 θ = \frac{5 π}{6} + 2 πn : θ = \frac{5 π}{18} + \frac{2 πn}{3}

Solve

3 θ = \frac{7 π}{6} + 2 πn : θ = \frac{7 π}{18} + \frac{2 πn}{3}

θ = \frac{5 π}{18} + \frac{2 πn}{3}, θ = \frac{7 π}{18} + \frac{2 πn}{3}

cot (x) = \frac{12}{5}

sin (x) = \frac{8}{13}

a, f = t sin (a t)

1 + cos (x) = 2 - 2 sin^{2} (x)

sin (θ - \frac{π}{4}) + 1 = 0

What is the general solution for cos(3θ)=-(sqrt(3))/2 ?
The general solution for cos(3θ)=-(sqrt(3))/2 is θ=(5pi}{18}+(2pin)/3 ,θ=(7pi)/(18)+\frac{2pin)/3