What is the general solution for 2sin(x)-sin(x)=0 ?

The general solution for 2sin(x)-sin(x)=0 is x=2pin,x=pi+2pin

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2sin(x)-sin(x)=0

2 sin (x) - sin (x) = 0

x = 2 πn, x = π + 2 πn

Solution steps

2 sin (x) - sin (x) = 0

Simplify

2 sin (x) - sin (x) : sin (x)

sin (x) = 0

General solutions for

sin (x) = 0

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 2 πn, x = π + 2 πn

cos^{2} (θ) - cos (θ) - 12 = 0

(sin (3 x) - 3) (cos (x) + 1) = 0

sin (c) = \frac{2}{π ( - cos ( c ) + 1 )}

csc^{2} (x) = - 2 cot (x)

tan^{2} (θ) + cot^{2} (θ) = - 1

What is the general solution for 2sin(x)-sin(x)=0 ?
The general solution for 2sin(x)-sin(x)=0 is x=2pin,x=pi+2pin