What is the general solution for (sin(3x)-3)(cos(x)+1)=0 ?

The general solution for (sin(3x)-3)(cos(x)+1)=0 is x=pi+2pin

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(sin(3x)-3)(cos(x)+1)=0

(sin (3 x) - 3) (cos (x) + 1) = 0

x = π + 2 πn

Solution steps

(sin (3 x) - 3) (cos (x) + 1) = 0

Solving each part separately

sin (3 x) - 3 = 0 or cos (x) + 1 = 0

sin (3 x) - 3 = 0 :

No Solution

cos (x) + 1 = 0 : x = π + 2 πn

Combine all the solutions

x = π + 2 πn

sin (c) = \frac{2}{π ( - cos ( c ) + 1 )}

csc^{2} (x) = - 2 cot (x)

tan^{2} (θ) + cot^{2} (θ) = - 1

sin^{2} (θ) + cos (2 θ) - cos (θ) = 0

4 cos^{2} (x - 3) = 0

What is the general solution for (sin(3x)-3)(cos(x)+1)=0 ?
The general solution for (sin(3x)-3)(cos(x)+1)=0 is x=pi+2pin