What is the general solution for 16tan^2(x)-1=0 ?

The general solution for 16tan^2(x)-1=0 is x=0.24497…+pin,x=-0.24497…+pin

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16tan^2(x)-1=0

16 tan^{2} (x) - 1 = 0

x = 0.24497 \dots + πn, x = - 0.24497 \dots + πn

Solution steps

16 tan^{2} (x) - 1 = 0

Solve by substitution

tan (x) = \frac{1}{4}, tan (x) = - \frac{1}{4}

tan (x) = \frac{1}{4} : x = arctan (\frac{1}{4}) + πn

tan (x) = - \frac{1}{4} : x = arctan (- \frac{1}{4}) + πn

Combine all the solutions

x = arctan (\frac{1}{4}) + πn, x = arctan (- \frac{1}{4}) + πn

Show solutions in decimal form

x = 0.24497 \dots + πn, x = - 0.24497 \dots + πn

sin^{2} (x) - sin (x) = 0, 0 \leq x \leq 2 π

sin (x + 3 7^{\circ}) = cos (2 x + 8)

sin (θ) = \frac{8}{17}, cos (θ) = \frac{15}{17}

tan (x) = 4746050429

cos^{2} (5 x) = 1

What is the general solution for 16tan^2(x)-1=0 ?
The general solution for 16tan^2(x)-1=0 is x=0.24497…+pin,x=-0.24497…+pin