What is the general solution for 11-sin(θ)=cos(2θ) ?

The general solution for 11-sin(θ)=cos(2θ) is No Solution for θ\in\mathbb{R}

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11-sin(θ)=cos(2θ)

11 - sin (θ) = cos (2 θ)

No Solution for θ \in R

Solution steps

11 - sin (θ) = cos (2 θ)

Subtract

cos (2 θ)

from both sides

11 - sin (θ) - cos (2 θ) = 0

Rewrite using trig identities

10 - sin (θ) + 2 sin^{2} (θ) = 0

Solve by substitution

sin (θ) = \frac{1}{4} + i \frac{79}{4}, sin (θ) = \frac{1}{4} - i \frac{79}{4}

sin (θ) = \frac{1}{4} + i \frac{79}{4} :

No Solution

sin (θ) = \frac{1}{4} - i \frac{79}{4} :

No Solution

Combine all the solutions

No Solution for θ \in R

2 cos^{2} (x) - 5 cos (x) = - 2

- 2 (cos (x) - 3) = 7

sin (x) + sin^{2} (x) = - cos^{2} (x)

cos (9 x) - cos (3 x) = sin (6 x)

1 - cos^{2} (θ) + 3 = 2 sin (θ) + 3

What is the general solution for 11-sin(θ)=cos(2θ) ?
The general solution for 11-sin(θ)=cos(2θ) is No Solution for θ\in\mathbb{R}