What is the general solution for tan(θ/2+pi/4)=-1,0<= θ<= 2pi ?

The general solution for tan(θ/2+pi/4)=-1,0<= θ<= 2pi is θ=pi

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tan(θ/2+pi/4)=-1,0<= θ<= 2pi

tan (\frac{θ}{2} + \frac{π}{4}) = - 1, 0 \leq θ \leq 2 π

θ = π

Solution steps

tan (\frac{θ}{2} + \frac{π}{4}) = - 1, 0 \leq θ \leq 2 π

General solutions for

tan (\frac{θ}{2} + \frac{π}{4}) = - 1

\frac{θ}{2} + \frac{π}{4} = \frac{3 π}{4} + πn

Solve

\frac{θ}{2} + \frac{π}{4} = \frac{3 π}{4} + πn : θ = 2 πn + π

θ = 2 πn + π

Solutions for the range

0 \leq θ \leq 2 π

θ = π

sin^{2} (x) = 2 cos (x) + 2, 0 \leq x \leq 2 π

tan^{4} (x) = tan^{4} (x) cos (x)

tan (x) sec (x) = 0

sin (x) + cos (x) = 1.2, sin (2 x)

2 cos (x) + 3 tan (x) = 3 sec (x)

What is the general solution for tan(θ/2+pi/4)=-1,0<= θ<= 2pi ?
The general solution for tan(θ/2+pi/4)=-1,0<= θ<= 2pi is θ=pi