What is the general solution for sin^2(x)-sin(x)cos(x)=0 ?

The general solution for sin^2(x)-sin(x)cos(x)=0 is x=2pin,x=pi+2pin,x= pi/4+pin

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sin^2(x)-sin(x)cos(x)=0

sin^{2} (x) - sin (x) cos (x) = 0

x = 2 πn, x = π + 2 πn, x = \frac{π}{4} + πn

Solution steps

sin^{2} (x) - sin (x) cos (x) = 0

Factor

sin^{2} (x) - sin (x) cos (x) : sin (x) (sin (x) - cos (x))

sin (x) (sin (x) - cos (x)) = 0

Solving each part separately

sin (x) = 0 or sin (x) - cos (x) = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) - cos (x) = 0 : x = \frac{π}{4} + πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{π}{4} + πn

cot (χ - \frac{π}{4}) = - 1

cos (3 x - 1) = 0

x, sec^{2} (x y) y = 0

tan (x + 7) = cot (4 x + 8)

43 cos (t) - 4 sin (t) = 0

What is the general solution for sin^2(x)-sin(x)cos(x)=0 ?
The general solution for sin^2(x)-sin(x)cos(x)=0 is x=2pin,x=pi+2pin,x= pi/4+pin