What is the general solution for 2sqrt(3)sin(4θ)=3 ?

The general solution for 2sqrt(3)sin(4θ)=3 is θ= pi/(12)+(pin)/2 ,θ= pi/6+(pin)/2

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2sqrt(3)sin(4θ)=3

23 sin (4 θ) = 3

θ = \frac{π}{12} + \frac{πn}{2}, θ = \frac{π}{6} + \frac{πn}{2}

Solution steps

23 sin (4 θ) = 3

Divide both sides by

23

sin (4 θ) = \frac{3}{2}

General solutions for

sin (4 θ) = \frac{3}{2}

4 θ = \frac{π}{3} + 2 πn, 4 θ = \frac{2 π}{3} + 2 πn

Solve

4 θ = \frac{π}{3} + 2 πn : θ = \frac{π}{12} + \frac{πn}{2}

Solve

4 θ = \frac{2 π}{3} + 2 πn : θ = \frac{π}{6} + \frac{πn}{2}

θ = \frac{π}{12} + \frac{πn}{2}, θ = \frac{π}{6} + \frac{πn}{2}

3 tan (3 x) = 3

8 cos (3 x) = 2

cot^{2} (θ) = 1

tan (\frac{x}{2}) = \frac{4 - π}{π}

sin^{2} (x) = sin^{2} (x) sec (x)

What is the general solution for 2sqrt(3)sin(4θ)=3 ?
The general solution for 2sqrt(3)sin(4θ)=3 is θ= pi/(12)+(pin)/2 ,θ= pi/6+(pin)/2