What is the general solution for sin(2θ-pi/3)=-1/2 ?

The general solution for sin(2θ-pi/3)=-1/2 is θ=pin+(3pi)/4 ,θ=pin+(13pi)/(12)

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sin(2θ-pi/3)=-1/2

sin (2 θ - \frac{π}{3}) = - \frac{1}{2}

θ = πn + \frac{3 π}{4}, θ = πn + \frac{13 π}{12}

Solution steps

sin (2 θ - \frac{π}{3}) = - \frac{1}{2}

General solutions for

sin (2 θ - \frac{π}{3}) = - \frac{1}{2}

2 θ - \frac{π}{3} = \frac{7 π}{6} + 2 πn, 2 θ - \frac{π}{3} = \frac{11 π}{6} + 2 πn

Solve

2 θ - \frac{π}{3} = \frac{7 π}{6} + 2 πn : θ = πn + \frac{3 π}{4}

Solve

2 θ - \frac{π}{3} = \frac{11 π}{6} + 2 πn : θ = πn + \frac{13 π}{12}

θ = πn + \frac{3 π}{4}, θ = πn + \frac{13 π}{12}

sec (x) + cos (x) = sin (x) tan (x)

7 cos (θ) + 20 = 0

sec^{2} (x) = \frac{1}{2} csc^{2} (x) + tan^{2} (x)

x, sin (x + 3 0^{\circ}) = tan (1 0^{\circ})

4 cos (2 θ) - 3 cos (θ) + 4 = - cos (θ) + 3

What is the general solution for sin(2θ-pi/3)=-1/2 ?
The general solution for sin(2θ-pi/3)=-1/2 is θ=pin+(3pi)/4 ,θ=pin+(13pi)/(12)