What is the general solution for -3cos(2x)=0 ?

The general solution for -3cos(2x)=0 is x= pi/4+pin,x=(3pi)/4+pin

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-3cos(2x)=0

- 3 cos (2 x) = 0

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

- 3 cos (2 x) = 0

Divide both sides by

- 3

cos (2 x) = 0

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

csc (x) + 1 = 0, 0 \leq x < 2 π

15 cos (x) = 7 + cos (x)

sec (x) = 1 - tan^{2} (x)

x, - sin (x y) y = 0

\frac{1}{cos ( x )} = \frac{5}{3}

What is the general solution for -3cos(2x)=0 ?
The general solution for -3cos(2x)=0 is x= pi/4+pin,x=(3pi)/4+pin