What is the general solution for cos(2x)=-1,0<= x<= 2pi ?

The general solution for cos(2x)=-1,0<= x<= 2pi is x= pi/2 ,x=(3pi)/2

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cos(2x)=-1,0<= x<= 2pi

cos (2 x) = - 1, 0 \leq x \leq 2 π

x = \frac{π}{2}, x = \frac{3 π}{2}

Solution steps

cos (2 x) = - 1, 0 \leq x \leq 2 π

General solutions for

cos (2 x) = - 1

2 x = π + 2 πn

Solve

2 x = π + 2 πn : x = \frac{π}{2} + πn

x = \frac{π}{2} + πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{2}, x = \frac{3 π}{2}

arccot (x) + arctan (3) = \frac{π}{2}

tan (x) = \frac{9}{7}

5 sin (4 x) = - 10 sin (2 x)

cot^{4} (x) = cot^{4} (x) sin (x)

2 - csc^{2} (x) = 0

What is the general solution for cos(2x)=-1,0<= x<= 2pi ?
The general solution for cos(2x)=-1,0<= x<= 2pi is x= pi/2 ,x=(3pi)/2