What is the general solution for sin(θ)=(sqrt(3))/2 ,0<= θ<2pi ?

The general solution for sin(θ)=(sqrt(3))/2 ,0<= θ<2pi is θ= pi/3 ,θ=(2pi)/3

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sin(θ)=(sqrt(3))/2 ,0<= θ<2pi

sin (θ) = \frac{3}{2}, 0 \leq θ < 2 π

θ = \frac{π}{3}, θ = \frac{2 π}{3}

Solution steps

sin (θ) = \frac{3}{2}, 0 \leq θ < 2 π

General solutions for

sin (θ) = \frac{3}{2}

θ = \frac{π}{3} + 2 πn, θ = \frac{2 π}{3} + 2 πn

Solutions for the range

0 \leq θ < 2 π

θ = \frac{π}{3}, θ = \frac{2 π}{3}

cos (θ) sin (θ) - 3 cos (θ) = 0

\frac{3}{2} = cos (θ)

7 sin (7 x) = 0

csc (θ) = \frac{5}{3}

- 5 sec (x) tan (x) = 0

What is the general solution for sin(θ)=(sqrt(3))/2 ,0<= θ<2pi ?
The general solution for sin(θ)=(sqrt(3))/2 ,0<= θ<2pi is θ= pi/3 ,θ=(2pi)/3