What is the general solution for cos(x)=(-sqrt(3))/2 ,0<= x<= 2pi ?

The general solution for cos(x)=(-sqrt(3))/2 ,0<= x<= 2pi is x=(5pi)/6 ,x=(7pi)/6

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cos(x)=(-sqrt(3))/2 ,0<= x<= 2pi

cos (x) = \frac{- 3}{2}, 0 \leq x \leq 2 π

x = \frac{5 π}{6}, x = \frac{7 π}{6}

Solution steps

cos (x) = \frac{- 3}{2}, 0 \leq x \leq 2 π

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

cos (x) = - \frac{3}{2}

General solutions for

cos (x) = - \frac{3}{2}

x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{5 π}{6}, x = \frac{7 π}{6}

- sin (t) = cos (t)

1 = sin (x^{2})

sin (3 x) = - sin (2 x)

cos (θ) = \frac{22}{65}

2 cos^{2} (θ) - 5 cos (θ) + 1 = 0

What is the general solution for cos(x)=(-sqrt(3))/2 ,0<= x<= 2pi ?
The general solution for cos(x)=(-sqrt(3))/2 ,0<= x<= 2pi is x=(5pi)/6 ,x=(7pi)/6