What is the general solution for cos(x)cos(2x)-sin(x)sin(2x)=0 ?

The general solution for cos(x)cos(2x)-sin(x)sin(2x)=0 is x= pi/6+(2pin)/3 ,x= pi/2+(2pin)/3

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cos(x)cos(2x)-sin(x)sin(2x)=0

cos (x) cos (2 x) - sin (x) sin (2 x) = 0

x = \frac{π}{6} + \frac{2 πn}{3}, x = \frac{π}{2} + \frac{2 πn}{3}

Solution steps

cos (x) cos (2 x) - sin (x) sin (2 x) = 0

Rewrite using trig identities

cos (x + 2 x) = 0

General solutions for

cos (x + 2 x) = 0

x + 2 x = \frac{π}{2} + 2 πn, x + 2 x = \frac{3 π}{2} + 2 πn

Solve

x + 2 x = \frac{π}{2} + 2 πn : x = \frac{π}{6} + \frac{2 πn}{3}

Solve

x + 2 x = \frac{3 π}{2} + 2 πn : x = \frac{π}{2} + \frac{2 πn}{3}

x = \frac{π}{6} + \frac{2 πn}{3}, x = \frac{π}{2} + \frac{2 πn}{3}

θ, x = 5 tan (θ)

cos (x) tan (x) cos (x) = 0, 0 \leq x \leq 2 π

3 sin (x) + 5 cos (x) + 5 = 0

2 cot (x) = 2

4 cos^{2} (x) + 2 = 3

What is the general solution for cos(x)cos(2x)-sin(x)sin(2x)=0 ?
The general solution for cos(x)cos(2x)-sin(x)sin(2x)=0 is x= pi/6+(2pin)/3 ,x= pi/2+(2pin)/3