What is the general solution for -1+sin(x)+cos^2(x)=0 ?

The general solution for -1+sin(x)+cos^2(x)=0 is x=2pin,x=pi+2pin,x= pi/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-1+sin(x)+cos^2(x)=0

- 1 + sin (x) + cos^{2} (x) = 0

x = 2 πn, x = π + 2 πn, x = \frac{π}{2} + 2 πn

Solution steps

- 1 + sin (x) + cos^{2} (x) = 0

Rewrite using trig identities

sin (x) - sin^{2} (x) = 0

Solve by substitution

sin (x) = 0, sin (x) = 1

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 1 : x = \frac{π}{2} + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{π}{2} + 2 πn

- sin (2 θ) + 2 cos (θ) = 0

2 sin (x) + 2 cos (x) = 1

2 cos (2 x) + 1 + 4 sin (x) = 0

tan (x) = - 1, tan (π + x) = y

sin (θ) sec (θ) - sin (θ) = 0

What is the general solution for -1+sin(x)+cos^2(x)=0 ?
The general solution for -1+sin(x)+cos^2(x)=0 is x=2pin,x=pi+2pin,x= pi/2+2pin