What is the general solution for tan(t)=-1/(sqrt(3)),-pi<t<= pi ?

The general solution for tan(t)=-1/(sqrt(3)),-pi<t<= pi is t=(5pi)/6 ,t=-pi/6

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tan(t)=-1/(sqrt(3)),-pi<t<= pi

tan (t) = - \frac{1}{3}, - π < t \leq π

t = \frac{5 π}{6}, t = - \frac{π}{6}

Solution steps

tan (t) = - \frac{1}{3}, - π < t \leq π

Simplify

- \frac{1}{3} : - \frac{3}{3}

General solutions for

tan (t) = - \frac{3}{3}

t = \frac{5 π}{6} + πn

Solutions for the range

- π < t \leq π

t = \frac{5 π}{6}, t = - \frac{π}{6}

sin (x) = \frac{- 4}{5}

16 = 7 - 7 cos (θ)

sin (θ) = \frac{5}{4}

2 cos (x) + 2 = 0

sin (θ) = \frac{15}{17}, cos (θ)

What is the general solution for tan(t)=-1/(sqrt(3)),-pi<t<= pi ?
The general solution for tan(t)=-1/(sqrt(3)),-pi<t<= pi is t=(5pi)/6 ,t=-pi/6