What is the general solution for tan(θ/2+pi/4)=1,0<= θ<= 2pi ?

The general solution for tan(θ/2+pi/4)=1,0<= θ<= 2pi is θ=0,θ=2pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan(θ/2+pi/4)=1,0<= θ<= 2pi

tan (\frac{θ}{2} + \frac{π}{4}) = 1, 0 \leq θ \leq 2 π

θ = 0, θ = 2 π

Solution steps

tan (\frac{θ}{2} + \frac{π}{4}) = 1, 0 \leq θ \leq 2 π

General solutions for

tan (\frac{θ}{2} + \frac{π}{4}) = 1

\frac{θ}{2} + \frac{π}{4} = \frac{π}{4} + πn

Solve

\frac{θ}{2} + \frac{π}{4} = \frac{π}{4} + πn : θ = 2 πn

θ = 2 πn

Solutions for the range

0 \leq θ \leq 2 π

θ = 0, θ = 2 π

sin (x + \frac{π}{6}) + sin (x - \frac{π}{6}) = \frac{3}{2}

c, s = \frac{sin ^{2} ( c )}{2}

3 sin^{2} (θ) + 4 cos^{2} (θ) = 4

tan^{2} (x) - 3 tan (x) - 2 = 0

sin (3 x) + 1 = cos (3 x)

What is the general solution for tan(θ/2+pi/4)=1,0<= θ<= 2pi ?
The general solution for tan(θ/2+pi/4)=1,0<= θ<= 2pi is θ=0,θ=2pi