What is the general solution for -2cos(x)+1=0 ?

The general solution for -2cos(x)+1=0 is x= pi/3+2pin,x=(5pi)/3+2pin

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-2cos(x)+1=0

- 2 cos (x) + 1 = 0

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solution steps

- 2 cos (x) + 1 = 0

Move

1

to the right side

- 2 cos (x) = - 1

Divide both sides by

- 2

cos (x) = \frac{1}{2}

General solutions for

cos (x) = \frac{1}{2}

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

18 sin (t) cos (t) = 6 sin (t)

8 sin (x) = 41 - 40 cos (x)

2 sin^{2} (x) + 9 sin (x) + 4 = 0

6 sin (2 x) = 6 cos (x)

cot (θ) = \frac{5}{12}

What is the general solution for -2cos(x)+1=0 ?
The general solution for -2cos(x)+1=0 is x= pi/3+2pin,x=(5pi)/3+2pin