What is the general solution for 0=cos^2(x)-sin^2(x) ?

The general solution for 0=cos^2(x)-sin^2(x) is x= pi/4+pin,x=(3pi)/4+pin

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0=cos^2(x)-sin^2(x)

0 = cos^{2} (x) - sin^{2} (x)

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

0 = cos^{2} (x) - sin^{2} (x)

Switch sides

cos^{2} (x) - sin^{2} (x) = 0

Rewrite using trig identities

cos (2 x) = 0

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

tan (x) = \frac{7.4}{9.3}

tan^{4} (x) - 1 = 0

sin (x) = 1, - π \leq x \leq 3 π

15 sin (x) + 19 = 14 sin (x) + 18

3 + 3 sin (θ) = \frac{6}{3 - 2 sin ( θ )}

What is the general solution for 0=cos^2(x)-sin^2(x) ?
The general solution for 0=cos^2(x)-sin^2(x) is x= pi/4+pin,x=(3pi)/4+pin