What is the general solution for 9tan^2(x)-27=0 ?

The general solution for 9tan^2(x)-27=0 is x= pi/3+pin,x=(2pi)/3+pin

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9tan^2(x)-27=0

9 tan^{2} (x) - 27 = 0

x = \frac{π}{3} + πn, x = \frac{2 π}{3} + πn

Solution steps

9 tan^{2} (x) - 27 = 0

Solve by substitution

tan (x) = 3, tan (x) = - 3

tan (x) = 3 : x = \frac{π}{3} + πn

tan (x) = - 3 : x = \frac{2 π}{3} + πn

Combine all the solutions

x = \frac{π}{3} + πn, x = \frac{2 π}{3} + πn

cos (x) = - 0.45

sin (4 x) cos (x) - sin (x) cos (4 x) = - \frac{1}{2}

4 tan (θ) - 1 = 0

cos^{2} (x) = 2 - cos (x)

8 sin (x) = cos (x) - 6

What is the general solution for 9tan^2(x)-27=0 ?
The general solution for 9tan^2(x)-27=0 is x= pi/3+pin,x=(2pi)/3+pin