What is the general solution for 2+2sin(θ)=cos^2(θ) ?

The general solution for 2+2sin(θ)=cos^2(θ) is θ=(3pi)/2+2pin

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2+2sin(θ)=cos^2(θ)

2 + 2 sin (θ) = cos^{2} (θ)

θ = \frac{3 π}{2} + 2 πn

Solution steps

2 + 2 sin (θ) = cos^{2} (θ)

Subtract

cos^{2} (θ)

from both sides

2 + 2 sin (θ) - cos^{2} (θ) = 0

Rewrite using trig identities

1 + sin^{2} (θ) + 2 sin (θ) = 0

Solve by substitution

sin (θ) = - 1

sin (θ) = - 1 : θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{3 π}{2} + 2 πn

2 cos (x) cos (2 x) - 2 sin (x) sin (2 x) = - 1

- 19 sin (θ) + \frac{19}{2} = 0

y, e^{8 x} = sin (x + 3 y)

π cos (π x) + π sin (π x) = 0

144 = 100 + 6.9 3^{2} - 2 \cdot 10 \cdot 6.93 \cdot cos (x)

What is the general solution for 2+2sin(θ)=cos^2(θ) ?
The general solution for 2+2sin(θ)=cos^2(θ) is θ=(3pi)/2+2pin