What is the general solution for 7sin(x)+1=5sin(x) ?

The general solution for 7sin(x)+1=5sin(x) is x=(7pi)/6+2pin,x=(11pi)/6+2pin

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7sin(x)+1=5sin(x)

7 sin (x) + 1 = 5 sin (x)

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Solution steps

7 sin (x) + 1 = 5 sin (x)

Solve by substitution

sin (x) = - \frac{1}{2}

sin (x) = - \frac{1}{2} : x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Combine all the solutions

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

sec (x) + tan (x) = 1, (0, 2 π)

cos^{2} (θ) - cos (θ) - 20 = 0

100.0191 = 180 - arctan (\frac{3.9254}{0.6936 - x})

- 9 sin (x) = 0

4 csc (θ) - 1 = - cot (θ) + 3 csc (θ)

What is the general solution for 7sin(x)+1=5sin(x) ?
The general solution for 7sin(x)+1=5sin(x) is x=(7pi)/6+2pin,x=(11pi)/6+2pin