What is the general solution for cos(2x)= 1/13 ?

The general solution for cos(2x)= 1/13 is x=(1.49379…)/2+pin,x=pi-(1.49379…)/2+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(2x)= 1/13

cos (2 x) = \frac{1}{13}

x = \frac{1.49379 \dots}{2} + πn, x = π - \frac{1.49379 \dots}{2} + πn

Solution steps

cos (2 x) = \frac{1}{13}

Apply trig inverse properties

2 x = arccos (\frac{1}{13}) + 2 πn, 2 x = 2 π - arccos (\frac{1}{13}) + 2 πn

Solve

2 x = arccos (\frac{1}{13}) + 2 πn : x = \frac{arccos ( \frac{1}{13} )}{2} + πn

Solve

2 x = 2 π - arccos (\frac{1}{13}) + 2 πn : x = π - \frac{arccos ( \frac{1}{13} )}{2} + πn

x = \frac{arccos ( \frac{1}{13} )}{2} + πn, x = π - \frac{arccos ( \frac{1}{13} )}{2} + πn

Show solutions in decimal form

x = \frac{1.49379 \dots}{2} + πn, x = π - \frac{1.49379 \dots}{2} + πn

cos (θ) = 0, D = R (θ)

\frac{sin ( θ )}{20} = \frac{sin ( 15 0 ^{\circ} )}{58.1826}

tan (x) = \frac{6}{3}

sin (A) = 0.40088

cos (x) - sin (3 x) = 0

What is the general solution for cos(2x)= 1/13 ?
The general solution for cos(2x)= 1/13 is x=(1.49379…)/2+pin,x=pi-(1.49379…)/2+pin