What is the general solution for sin^2(x)-9cos(x)+9=0 ?

The general solution for sin^2(x)-9cos(x)+9=0 is x=2pin

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sin^2(x)-9cos(x)+9=0

sin^{2} (x) - 9 cos (x) + 9 = 0

x = 2 πn

Solution steps

sin^{2} (x) - 9 cos (x) + 9 = 0

Rewrite using trig identities

10 - cos^{2} (x) - 9 cos (x) = 0

Solve by substitution

cos (x) = - 10, cos (x) = 1

cos (x) = - 10 :

No Solution

cos (x) = 1 : x = 2 πn

Combine all the solutions

x = 2 πn

sinh (x) = \frac{8}{15}

cos (x) = \frac{13}{16}

tan^{2} (x) - 4 tan (x) + 3 = 0

sin (x) + sin (3 x) = cos (x)

2 sin^{2} (x) = 3 (1 - cos (x))

What is the general solution for sin^2(x)-9cos(x)+9=0 ?
The general solution for sin^2(x)-9cos(x)+9=0 is x=2pin