What is the general solution for cos(θ)=((sin(60))/(1.28)) ?

The general solution for cos(θ)=((sin(60))/(1.28)) is θ=0.82768…+360n,θ=360-0.82768…+360n

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cos(θ)=((sin(60))/(1.28))

cos (θ) = (\frac{sin ( 6 0 ^{\circ} )}{1.28})

θ = 0.82768 \dots + 36 0^{\circ} n, θ = 36 0^{\circ} - 0.82768 \dots + 36 0^{\circ} n

Solution steps

cos (θ) = (\frac{sin ( 6 0 ^{\circ} )}{1.28})

sin (6 0^{\circ}) = \frac{3}{2}

cos (θ) = \frac{\frac{3}{2}}{1.28}

Simplify

\frac{\frac{3}{2}}{1.28} : \frac{3}{2.56}

Apply trig inverse properties

θ = arccos (\frac{3}{2.56}) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (\frac{3}{2.56}) + 36 0^{\circ} n

Show solutions in decimal form

θ = 0.82768 \dots + 36 0^{\circ} n, θ = 36 0^{\circ} - 0.82768 \dots + 36 0^{\circ} n

4 cos^{2} (x) - 3 cos (x) - 1 = 0

2 sin^{2} (\frac{x}{3}) = 1

cos (2 x) = 3 - 5 sin (x)

4 cos^{2} (x) + 43 sin (x) = 7

cos (2 θ) - sin (θ) cos (θ) = 0

What is the general solution for cos(θ)=((sin(60))/(1.28)) ?
The general solution for cos(θ)=((sin(60))/(1.28)) is θ=0.82768…+360n,θ=360-0.82768…+360n