What is the general solution for 6cos(x)+sqrt(18)=0 ?

The general solution for 6cos(x)+sqrt(18)=0 is x=(3pi)/4+2pin,x=(5pi)/4+2pin

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6cos(x)+sqrt(18)=0

6 cos (x) + 18 = 0

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

Solution steps

6 cos (x) + 18 = 0

18 = 32

6 cos (x) + 32 = 0

Move

32

to the right side

6 cos (x) = - 32

Divide both sides by

6

cos (x) = - \frac{2}{2}

General solutions for

cos (x) = - \frac{2}{2}

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

cos^{2} (x) = \frac{1 + cos ^{2} ( x )}{2}

\frac{2}{2} = cos (x)

10 sin (θ) + 1 = 3 - 2 sin (θ)

sin (x) cos (2 x) - cos (x) sin (2 x) = \frac{3}{2}

5 sin^{2} (x) + 3 sin (x) = 1

What is the general solution for 6cos(x)+sqrt(18)=0 ?
The general solution for 6cos(x)+sqrt(18)=0 is x=(3pi)/4+2pin,x=(5pi)/4+2pin