What is the general solution for -2sin(3θ)=1 ?

The general solution for -2sin(3θ)=1 is θ=(7pi}{18}+(2pin)/3 ,θ=(11pi)/(18)+\frac{2pin)/3

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-2sin(3θ)=1

- 2 sin (3 θ) = 1

θ = \frac{7 π}{18} + \frac{2 πn}{3}, θ = \frac{11 π}{18} + \frac{2 πn}{3}

Solution steps

- 2 sin (3 θ) = 1

Divide both sides by

- 2

sin (3 θ) = - \frac{1}{2}

General solutions for

sin (3 θ) = - \frac{1}{2}

3 θ = \frac{7 π}{6} + 2 πn, 3 θ = \frac{11 π}{6} + 2 πn

Solve

3 θ = \frac{7 π}{6} + 2 πn : θ = \frac{7 π}{18} + \frac{2 πn}{3}

Solve

3 θ = \frac{11 π}{6} + 2 πn : θ = \frac{11 π}{18} + \frac{2 πn}{3}

θ = \frac{7 π}{18} + \frac{2 πn}{3}, θ = \frac{11 π}{18} + \frac{2 πn}{3}

sin (θ) = 0.31

sin (θ) = 0.39

sin (θ) = 0.06

2 cos (t - \frac{π}{3}) = 0

sin (x) + 2 = 2.5

What is the general solution for -2sin(3θ)=1 ?
The general solution for -2sin(3θ)=1 is θ=(7pi}{18}+(2pin)/3 ,θ=(11pi)/(18)+\frac{2pin)/3