What is the general solution for sin(4x)-1=0 ?

The general solution for sin(4x)-1=0 is x= pi/8+(pin)/2

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sin(4x)-1=0

sin (4 x) - 1 = 0

x = \frac{π}{8} + \frac{πn}{2}

Solution steps

sin (4 x) - 1 = 0

Move

1

to the right side

sin (4 x) = 1

General solutions for

sin (4 x) = 1

4 x = \frac{π}{2} + 2 πn

Solve

4 x = \frac{π}{2} + 2 πn : x = \frac{π}{8} + \frac{πn}{2}

x = \frac{π}{8} + \frac{πn}{2}

9 cos (θ) = - 33 sin (- θ)

1 - cos^{2} (x) = 2 sin (x)

3 sec (- x) = 4 sec (x) + 1

sin (2 x) - 2 sin^{2} (x) = 0

4 sin (2 x - 0.4) - 5 cos (2 x - 0.4) = 0

What is the general solution for sin(4x)-1=0 ?
The general solution for sin(4x)-1=0 is x= pi/8+(pin)/2