Is tan(θ)=(sin(θ))/(cos(θ)) ?

The answer to whether tan(θ)=(sin(θ))/(cos(θ)) is True

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prove tan(θ)=(sin(θ))/(cos(θ))

prove

tan (θ) = \frac{sin ( θ )}{cos ( θ )}

True

Solution steps

tan (θ) = \frac{sin ( θ )}{cos ( θ )}

Use the basic trigonometric identity:

tan (x) = \frac{sin ( x )}{cos ( x )}

\Rightarrow True

(sin^{2} (x) - 1) (sec^{2} (x) - 1) = - sin^{2} (x)

tan^{2} (x) = sec^{2} (x) - 1

\frac{1}{cot ( x ) + 1} + \frac{1}{tan ( x ) + 1} = 1

sin^{2} (x) + cos (2 x) = cos^{2} (x)

\frac{1 - cot ^{2} ( x )}{tan ^{2} ( x ) - 1} = cot^{2} (x)

Is tan(θ)=(sin(θ))/(cos(θ)) ?
The answer to whether tan(θ)=(sin(θ))/(cos(θ)) is True