Is 1-(sin^2(θ))/(1-cos(θ))=-cos(θ) ?

The answer to whether 1-(sin^2(θ))/(1-cos(θ))=-cos(θ) is True

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prove 1-(sin^2(θ))/(1-cos(θ))=-cos(θ)

prove

1 - \frac{sin ^{2} ( θ )}{1 - cos ( θ )} = - cos (θ)

True

Solution steps

1 - \frac{sin ^{2} ( θ )}{1 - cos ( θ )} = - cos (θ)

Manipulating left side

1 - \frac{sin ^{2} ( θ )}{1 - cos ( θ )}

Rewrite using trig identities

= - cos (θ)

We showed that the two sides could take the same form

\Rightarrow True

(1 - sin^{2} (x)) tan (x) = cos (x) sin (x)

cot (x) = \frac{1}{tan ( x )}

(1 - cos (θ)) (1 + cos (θ)) = \frac{1}{csc ^{2} ( θ )}

sec (- x) sin (x) = tan (x)

cos (θ) csc (θ) tan (θ) = 1

Is 1-(sin^2(θ))/(1-cos(θ))=-cos(θ) ?
The answer to whether 1-(sin^2(θ))/(1-cos(θ))=-cos(θ) is True